CATAlgebra > EasyEntered answer:✅ Correct Answer: 2Related questions:CAT 2018 Slot 2Let f(x)=f(x)=f(x)= max{5x5x5x, 52−2x252-2x^252−2x2}, where xxx is any positive real number. Then the minimum possible value of f(x)f(x)f(x) isCAT 2017 Slot 2The minimum possible value of the sum of the squares of the roots of the equation x2+(a+3)x−(a+5)=0x^{2}+(a+3) x-(a+5)=0x2+(a+3)x−(a+5)=0 isCAT 2020 Slot 1Among 100100100 students, x1x_{1}x1 have birthdays in January, x2x_{2}x2 have birthday in February, and so on. If x0=max(x1,x2,…,x12)x_{0}=\max \left(x_{1}, x_{2}, \ldots , x_{12}\right)x0=max(x1,x2,…,x12), then the smallest possible value of x0x_{0}x0 is