CATAlgebra > Easy−16-16−16−15-15−15−12-12−12−20-20−20✅ Correct Option: 1Related questions:CAT 2023 Slot 3Suppose f(x,y)f(x, y)f(x,y) is a real valued function such that f(3x+2y,2x−5y)=19xf(3x + 2y, 2x- 5y) = 19xf(3x+2y,2x−5y)=19x, for all real numbers xxx and yyy. The value of xxx for which f(x,2x)=27f(x, 2x) = 27f(x,2x)=27, isCAT 2019 Slot 1Consider a function fff satisfying f(x+y)=f(x)f(y)f(\mathrm{x}+\mathrm{y})=f(\mathrm{x}) \mathrm{f}(\mathrm{y})f(x+y)=f(x)f(y) where x,yx , yx,y are positive integers, and f(1)=2f(1)=2f(1)=2. If f(a+1)+f(a+2)+……+f(a+n)=f(\mathrm{a}+1)+f(\mathrm{a}+2)+\ldots \ldots+f(\mathrm{a}+\mathrm{n})=f(a+1)+f(a+2)+……+f(a+n)= 16(2n−1)16\left(2^{n}-1\right)16(2n−1) then a is equal toCAT 2022 Slot 3Let r be a real number and f(x)={2x−rif x≥r1if x<rf(x) = \begin{cases} 2x-r & \text{if } x \ge r \\ 1 & \text{if } x < r \end{cases}f(x)={2x−r1if x≥rif x<r. Then, the equation f(x)=f(f(x))f(x) = f(f(x))f(x)=f(f(x)) holds for all real values of x where.