CATAlgebra > Medium797979848484838383868686✅ Correct Option: 1Related questions:CAT 2021 Slot 1The natural numbers are divided into groups as (1), (2,3,4),(5,6,7,8,9),….(2,3,4),(5,6,7,8,9), \ldots .(2,3,4),(5,6,7,8,9),….. and so on. Then, the sum of the numbers in the 15th group is equal toCAT 2017 Slot 1Let a1,a2,……...a3na_{1}, a_{2}, \ldots \ldots . . . a_{3 n}a1,a2,……...a3n be an arithmetic progression with a1=3a_{1}=3a1=3 and a2=7a_{2}=7a2=7. If a1+a2+….+a3n=1830a_{1}+a_{2}+\ldots .+a_{3 n}=1830a1+a2+….+a3n=1830, then what is the smallest positive integer mmm such that m(a1+a2+….+an)>1830m\left(a_{1}+a_{2}+\ldots .+a_{n}\right)>1830m(a1+a2+….+an)>1830 ?CAT 2017 Slot 2If a1=12×5,a2=15×8,a3=18×11\mathrm{a}_{1}=\frac{1}{2 \times 5}, \mathrm{a}_{2}=\frac{1}{5 \times 8}, \mathrm{a}_{3}=\frac{1}{8 \times 11}a1=2×51,a2=5×81,a3=8×111, then a1,+a2,+a3,+…..a100\mathrm{a}_{1,}+\mathrm{a}_{2,}+\mathrm{a}_{3,}+\ldots . . \mathrm{a}_{100}a1,+a2,+a3,+…..a100 is