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Algebra

Hard

$[3,\sqrt{10}]\cup[5,\sqrt{26}]$

$[3,\sqrt{10}]\cup[4,\sqrt{17}]\cup\{6\}$

$[3,\sqrt{10})\cup[5,\sqrt{26})\cup\{6\}$

$(4,\sqrt{18})\cup[5,\sqrt{27})\cup\{6\}$

✅ Correct Option: 3

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