CATAlgebra > Hard[3,10]∪[5,26][3,\sqrt{10}]\cup[5,\sqrt{26}][3,10]∪[5,26][3,10]∪[4,17]∪{6}[3,\sqrt{10}]\cup[4,\sqrt{17}]\cup\{6\}[3,10]∪[4,17]∪{6}(3,10)∪[5,26)∪{6}(3,\sqrt{10})\cup[5,\sqrt{26})\cup\{6\}(3,10)∪[5,26)∪{6}(4,18)∪[5,27)∪{6}(4,\sqrt{18})\cup[5,\sqrt{27})\cup\{6\}(4,18)∪[5,27)∪{6}✅ Correct Option: 3Related questions:CAT 2022 Slot 3Let r be a real number and f(x)={2x−rif x≥r1if x<rf(x) = \begin{cases} 2x-r & \text{if } x \ge r \\ 1 & \text{if } x < r \end{cases}f(x)={2x−r1if x≥rif x<r. Then, the equation f(x)=f(f(x))f(x) = f(f(x))f(x)=f(f(x)) holds for all real values of x where.CAT 2024 Slot 3For any non-zero real number x, let f(x)+2f(1x)=3xf(x) + 2 f(\frac{1}{x}) = 3xf(x)+2f(x1)=3x. Then, the sum of all possible values of xxx for which f(x)=3f(x) = 3f(x)=3, isCAT 2018 Slot 1If f(x+2)=f(x)+f(x+1)f(x + 2) = f(x) + f(x + 1)f(x+2)=f(x)+f(x+1) for all positive integers xxx, and f(11)=91f(11) = 91f(11)=91, f(15)=617f(15) = 617f(15)=617, then f(10)f(10)f(10) equals