CATAlgebra > Medium−5150-5150−5150−5051-5051−5051−5050-5050−5050−5151-5151−5151✅ Correct Option: 3Related questions:2025 Slot 1For any natural number kkk, let ak=3ka_k = 3^kak=3k. The smallest natural number mmm for which {(a1)1×(a2)2×…×(a20)20}<{a21×a22×…×a(20+m)}\{(a_1)^1 \times (a_2)^2 \times \ldots \times (a_{20})^{20}\} < \{a_{21} \times a_{22} \times \ldots \times a_{(20+m)}\}{(a1)1×(a2)2×…×(a20)20}<{a21×a22×…×a(20+m)}, isCAT 2019 Slot 2Let a1,a2,...a_1, a_2, ...a1,a2,... be integers such that a1−a2+a3−a4+...+(−1)n−1an=na_1 - a_2 + a_3 - a_4 + ... + (-1)^{n - 1} a_n = na1−a2+a3−a4+...+(−1)n−1an=n, for all n≥1n \ge 1n≥1. Then a51+a52+...+a1023a_{51} + a_{52} + ... + a_{1023}a51+a52+...+a1023 equalsCAT 2017 Slot 2An infinite geometric progression a1,a2,a3,...a_1, a_2, a_3,...a1,a2,a3,... has the property that an=3(an+1+an+2+....)a_n = 3(a_{n+1} + a_{n+2} +....)an=3(an+1+an+2+....) for every n≥1n \ge 1n≥1. If the sum a1+a2+a3+.....=32a_1 + a_2 + a_3 +..... = 32a1+a2+a3+.....=32, then a5a_5a5 is