CAT (QA) PYQs

The sum of digits of the number $(625)^{65} \times (128)^{36}$, is

In a six-digit number, the sixth, that is, the rightmost, digit is the sum of the first three digits, the fifth digit is the sum of first two digits, the third digit is equal to the first digit, the second digit is twice the first digit and the fourth digit is the sum of fifth and sixth digits. Then, the largest possible value of the fourth digit is

How many three-digit numbers are greater than $100$ and increase by $198$ when the three digits are arranged in the reverse order?